fix: proofread Probability part#327
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Proofread the chapters in the Probability part (tex/measure/randvar.tex, large-laws.tex, martingale.tex). Fixes are mostly typos, grammar, and small calculation errors; two are corrections to mathematical arguments and are called out in the PR description for review. Co-Authored-By: Claude Opus 4.8 <[email protected]> Claude-Session: https://claude.ai/code/session_013cZCGGkrXhnb2j2oWVYkT7
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Proofreading pass over the Probability part (issue #315):
tex/measure/randvar.tex,tex/measure/large-laws.tex, andtex/measure/martingale.tex. (randvar.texneeded no changes.)Most fixes are minor (typos/grammar). A few are small calculation fixes, and two are corrections to mathematical arguments that I'd appreciate a second look at (flagged below).
Calculation / math fixes
martingale.tex(casino example): the winnings on the third bet were computed as$1000 - $20 - $2 = $978, but betting$100wins$100, so it should be$100 - $20 - $2 = $78.martingale.tex(ballot example): the third illustrative martingale$X_1 = \frac94 (A_1-B_1)^2$gives\EE[X_1] = 3, not the intended1. The coefficient should be\frac34(since\EE[(A_1-B_1)^2] = \frac43).martingale.tex(product martingale):\EE(Y_n \mid \dots) = \EE[Y_n]\cdot Y_{n-1}should be\EE[X_n]\cdot Y_{n-1}— the conditional expectation factors out the knownY_{n-1}, leaving\EE[X_n] = 1.large-laws.tex(Kolmogorov inequality proof): the cross term in the expansion of(S_i + (S_n-S_i))^2was missing its factor of2. (The term is0, so the conclusion is unaffected, but the expansion was incorrect.)large-laws.tex("Quantifier hell" solution): the a.s.-convergence conclusion read\lim_n |X-X_n| = 1; it should be= 0(the surrounding argument bounds it by1/mfor everym).large-laws.tex: added the missing\,d\muto\EE[X_i] = \int_\Omega X_i(\omega).martingale.tex, "Stopped supermartingales are still supermartingales" proof: the increment decomposition was written asX_{n-1} + \mathbf 1_{\tau = n-1}(X_n - X_{n-1})bounded byX_{n-1}. As written this identity does not hold (e.g. when\tau = n-1or\tau \ge n). I corrected it to the standard decompositionX_{\tau\wedge(n-1)} + \mathbf 1_{\tau \ge n}(X_n - X_{n-1}) \le X_{\tau\wedge(n-1)}, which is what the supermartingale conclusion requires. Worth a sanity check.martingale.tex, optional stopping "Finite bets" hypothesis: changed the conditioning from\SF_nto\SF_{n-1}in\EE(|X_n - X_{n-1}| \mid \SF_n). Conditioning on\SF_nmakes the increment already measurable (so the conditional expectation is trivial); the standard bounded-increments hypothesis conditions on\SF_{n-1}.Typos / grammar
$X$if if for every" → removed duplicate "if".X \colon \Omega \to \{0,1,2\}was inconsistent with the eventsX=1,2,3defined just below →\{1,2,3\}.$\sigma$-algebra on$\SF$" → "on$\Omega$".$X+Y=3$" → "where".Closes the Probability checkbox in #315.
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