平分三角形问题#21
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待配图完成后再Ready for review |
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如此看来分类文件夹的名字要和分类保持一致才行，空格用-号 |
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This pull request fixes #22 |
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| 1.在$\bigtriangleup ABC$中，作出三条中线，设为$AD, BE, CF$.<br> | ||
| 2.选取其中一角，这里选$\angle A$，取**这个角的两边上的中线**$BE, CF$的中点分别为$P, Q$.<br> | ||
| 3.以$AC, AB$所在直线为渐近线，作与$CF, BE$切于$P,Q$两点的**双曲线段**[^2].<br> | ||
| 4.对$\angle B, \angle C$重复操作2,3.<br> | ||
| 5.能够平分$\bigtriangleup ABC$面积的直线构成的直线系，就是上面作出来的三条双曲线段的所有切线的集合. |
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| 1.在$\bigtriangleup ABC$中，作出三条中线，设为$AD, BE, CF$.<br> | |
| 2.选取其中一角，这里选$\angle A$，取**这个角的两边上的中线**$BE, CF$的中点分别为$P, Q$.<br> | |
| 3.以$AC, AB$所在直线为渐近线，作与$CF, BE$切于$P,Q$两点的**双曲线段**[^2].<br> | |
| 4.对$\angle B, \angle C$重复操作2,3.<br> | |
| 5.能够平分$\bigtriangleup ABC$面积的直线构成的直线系，就是上面作出来的三条双曲线段的所有切线的集合. | |
| 1. 在 $\bigtriangleup ABC$ 中，作出三条中线，设为 $AD, BE, CF$. | |
| 2. 选取其中一角，这里选 $\angle A$，取**这个角的两边上的中线** $BE, CF$ 的中点分别为 $P, Q$. | |
| 3. 以 $AC, AB$ 所在直线为渐近线，作与 $CF, BE$ 切于 $P,Q$ 两点的**双曲线段**[^2]. | |
| 4. 对 $\angle B, \angle C$ 重复操作2,3. | |
| 5. 能够平分 $\bigtriangleup ABC$ 面积的直线构成的直线系，就是上面作出来的三条双曲线段的所有切线的集合. |
行间公式的美元符号最好有空格分开，就像这样：
选取其中一角，这里选 $\angle A$ ，取**这个角的两边上的中线** $BE, CF$ 的中点分别为 $P, Q$这一段还有问题, 你可以用有序列表而不是 <br> 手动换行
渲染时没有换行是因为你的序号后面没有加空格，要这样写：1. 而不是 1.
| tags: | ||
| - Femboy's Dessert House | ||
| - 全错排 | ||
| - 排列组合 |
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| - 排列组合 |
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fix #22