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80 lines (66 loc) · 4.38 KB
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\documentclass[12pt]{article}
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\pmcanonicalname{ProofOfFundamentalTheoremOfAlgebradueToDAlembert}
\pmcreated{2013-03-22 14:36:06}
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\pmtitle{proof of fundamental theorem of algebra (due to d'Alembert)}
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\pmtype{Proof}
\pmcomment{trigger rebuild}
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\begin{document}
This proof, due to d'Alembert, relies on the following three facts:
\begin{itemize}
\item Every polynomial with real coefficients which is of odd order has a real root. (This is a corollary of the intermediate value theorem.
\item Every second order polynomial with complex coefficients has two complex roots.
\item For every polynomial $p$ with real coefficients, there exists a field $E$ in which the polynomial may be factored into linear terms. (For more information, see the entry ``splitting field''.)
\end{itemize}
Note that it suffices to prove that every polynomial with real coefficients has a complex root. Given a polynomial with complex coefficients, one can construct a polynomial with real coefficients by multiplying the polynomial by its complex conjugate. Any root of the resulting polynomial will either be a root of the original polynomial or the complex conjugate of a root.
The proof proceeds by induction. Write the degree of the polynomial as $2^n (2m+1)$. If $n = 0$, then we know that it must have a real root. Next, assume that we already have shown that the fundamental theorem of algebra holds whenver $n < N$. We shall show that any polynomial of degree $2^N (2m+1)$ has a complex root if a certain other polynomial of order $2^{N-1} (2m' + 1)$ has a root. By our hypothesis, the other polynomial does have a root, hence so does the original polynomial. Hence, by induction on $n$, every polynomial with real coefficients has a complex root.
Let $p$ be a polynomial of order $d = 2^N (2m+1)$ with real coefficients. Let its factorization over the extension field $E$ be
$$p(x) = (x - r_1) (x - r_2) \cdots (x - r_d)$$
Next construct the $d(d-1)/2 = 1$ polynomials
$$q_k (x) = \prod_{i < j} (x - r_i - r_j - k r_i r_j)$$
where $k$ is an integer between $1$ and $d(d-1)/2 = 1$. Upon expanding the product and collecting terms, the coefficient of each power of $x$ is a symmetric function of the roots $r_i$. Hence it can be expressed in terms of the coefficients of $p$, so the coefficients of $q_k$ will all be real.
Note that the order of each $q_k$ is $d(d-1)/2 = 2^{N-1} (2m+1) (2^N (2m+1) - 1)$. Hence, by the induction hypothesis, each $q_k$ must have a complex root. By construction, each root of $q_k$ can be expressed as $r_i + r_j + k r_i r_j$ for some choice of integers $i$ and $j$. By the pigeonhole principle, there must exist integers $i, j, k_1, k_2$ such that both
$$u = r_i + r_j + k_1 r_i r_j$$
and
$$v = r_i + r_j + k_2 r_i r_j$$
are complex. But then $r_i$ and $r_j$ must be complex as well. because they are roots of the polynomial
$$x^2 + bx + c$$
where
$$b = -{k_2 u + k_1 v \over (k_1 + k_2)}$$
and
$$c = {u - v \over k_1 - k_2}$$
\textbf{Note.}\, D'Alembert was an avid supporter (in fact, the co-editor) of the famous French philosophical encyclopaedia. Therefore it is a fitting tribute to have his proof appear in the web pages of this encyclopaedia.
\begin{thebibliography}{8}
\bibitem{J}{\sc Jean le Rond D'Alembert}: ``Recherches sur le calcul int\'egral''.
\, \emph{Histoire de l'Acad\'mie Royale des Sciences et Belles Lettres}, ann\'ee MDCCXLVI, 182--224. Berlin (1746).
\bibitem{R}{\sc R. Argand}: ``R\'eflexions sur la nouvelle th\'eorie d'analyse''.\, \emph{Annales de math\'ematiques} \textbf{5}, 197--209 (1814).
\end{thebibliography}
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\end{document}