From 28594d15a2be0e43dc24a8162d1884e9f7a23b32 Mon Sep 17 00:00:00 2001 From: Patrick Rabau <70125716+prabau@users.noreply.github.com> Date: Thu, 2 Jul 2026 17:56:19 -0400 Subject: [PATCH 1/2] T913: cid + not discrete => uncountable pi-character --- theorems/T000913.md | 16 ++++++++++++++++ 1 file changed, 16 insertions(+) create mode 100644 theorems/T000913.md diff --git a/theorems/T000913.md b/theorems/T000913.md new file mode 100644 index 000000000..3c609c511 --- /dev/null +++ b/theorems/T000913.md @@ -0,0 +1,16 @@ +--- +uid: T000913 +if: + and: + - P000168: true + - P000052: false +then: + P000244: false +--- + +Let $x$ be a non-isolated point in $X$ +and let $\mathscr V$ be a countable collection of nonempty open sets. +To show $X$ has uncountable $\pi$-character, we show that $\mathscr V$ is not a local $\pi$-base for $x$. +Each $V\in\mathscr V$ contains a point $x_V\ne x$. +The set $F:=\{x_V:V\in\mathscr V\}$ is countable, hence closed since $X$ is {P168}. +Then $X\setminus F$ is an open neighborhood of $x$ not containing any $V\in\mathscr V$. From e0e742f4b079636d36d481a260918a7e9ca00a26 Mon Sep 17 00:00:00 2001 From: Patrick Rabau <70125716+prabau@users.noreply.github.com> Date: Thu, 2 Jul 2026 23:02:39 -0400 Subject: [PATCH 2/2] clearer --- theorems/T000913.md | 5 +++-- 1 file changed, 3 insertions(+), 2 deletions(-) diff --git a/theorems/T000913.md b/theorems/T000913.md index 3c609c511..dc8c39857 100644 --- a/theorems/T000913.md +++ b/theorems/T000913.md @@ -12,5 +12,6 @@ Let $x$ be a non-isolated point in $X$ and let $\mathscr V$ be a countable collection of nonempty open sets. To show $X$ has uncountable $\pi$-character, we show that $\mathscr V$ is not a local $\pi$-base for $x$. Each $V\in\mathscr V$ contains a point $x_V\ne x$. -The set $F:=\{x_V:V\in\mathscr V\}$ is countable, hence closed since $X$ is {P168}. -Then $X\setminus F$ is an open neighborhood of $x$ not containing any $V\in\mathscr V$. +One characterization of {P168} is that every countable set is closed. +So the countable set $F:=\{x_V:V\in\mathscr V\}$ is closed in $X$. +Its complement $X\setminus F$ is an open neighborhood of $x$ not containing any $V\in\mathscr V$.