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Copy pathcf-C - Perfect Team - code.cpp
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46 lines (43 loc) · 1.6 KB
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#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
#define pb push_back
#define io ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL);
#define all(s) s.begin(),s.end()
#define rep(i, a, b) for(ll i = a; i < b; i++)
#define rr(v) for(auto &val:v)
#define _max(v) *max_element(v.begin(), v.end())
#define _min(v) *min_element(v.begin(), v.end())
#define ms(s, n) memset(s, n, sizeof(s))
#define print(v) for(ll i=0; i<v.size(); i++) {cout<<v[i]<< " ";} cout<< endl;
ll raised(ll x, ll y){ll res = 1;while (y > 0){ if (y & 1){res = res*x;} y = y>>1;x = x*x;}return res;}
ll raisedmod(ll x, ll y, ll p){int res = 1;x = x % p;while (y > 0){if (y & 1){res = (res*x) % p;}y = y>>1; x = (x*x) % p;}return res;}
ll gcd(ll a, ll b) { if (b == 0)return a; return gcd(b, a % b);}
ll fact(ll n){ll res = 1; for (ll i = 2; i <= n; i++) res = res * i; return res; }
ll nCr(ll n, ll r){ return fact(n) / (fact(r) * fact(n - r));}
#define mod 1e9+7
// for minimising n-(x+y) x=draws, y=loses, so we maximise x+y and hence n-(x+y)decreases
int main()
{
io;
ll t; cin >> t;
//t=1;
while(t--)
{
ll a, b, c; cin >> a >> b >> c;
ll minval=min(a, b);
minval =min(minval, c);
ll ans=0;
ans+=minval;
a-=minval; b-=minval; c-=minval;
if(a==0 || b==0) cout << ans << endl;
else
{
minval=min(a, b);
ll maxval=max(a, b);
if(maxval>=minval*2) cout<< ans+minval << endl;
else cout<< ans+(minval+maxval)/3<< endl;
}
}
return 0;
}