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453-Minimum-Moves-to-Equal-Array-Elements.js
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46 lines (40 loc) · 1.07 KB
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/**
* https://leetcode.com/problems/minimum-moves-to-equal-array-elements/description/
* Difficulty:Easy
*
* Given a non-empty integer array of size n, find the minimum number of moves required to make all array elements equal, where a move is incrementing n - 1 elements by 1.
* Example:
* Input:
* [1,2,3]
* Output:
* 3
* Explanation:
* Only three moves are needed (remember each move increments two elements):
* [1,2,3] => [2,3,3] => [3,4,3] => [4,4,4]
*
*/
/**
*
* reverse thinking!
*
* Adding 1 to n - 1 elements is the same as subtracting 1 from one element
*
* goal of making the elements in the array equal.
* So, best way to do this is make all the elements in the array equal to the min element.
*/
/**
* @param {number[]} nums
* @return {number}
*/
var minMoves = function (nums) {
var min = nums[0];
for (var i = 1; i < nums.length; i++) {
min = Math.min(min, nums[i]);
}
var ret = 0;
for (i = 0; i < nums.length; i++) {
ret += nums[i] - min;
}
return ret;
};
console.log(minMoves([1, 999, 1000]));