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11. Deepest Leaves Sum.cpp
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65 lines (56 loc) · 1.37 KB
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/*
Deepest Leaves Sum
==================
Given the root of a binary tree, return the sum of values of its deepest leaves.
Example 1:
Input: root = [1,2,3,4,5,null,6,7,null,null,null,null,8]
Output: 15
Example 2:
Input: root = [6,7,8,2,7,1,3,9,null,1,4,null,null,null,5]
Output: 19
Constraints:
The number of nodes in the tree is in the range [1, 104].
1 <= Node.val <= 100
Hint #1
Traverse the tree to find the max depth.
Hint #2
Traverse the tree again to compute the sum required.
*/
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution
{
public:
int deepestLeavesSum(TreeNode *root)
{
int ans = 0;
queue<TreeNode *> pending;
pending.push(root);
while (pending.size())
{
int size = pending.size();
int curr_ans = 0;
for (int i = 0; i < size; ++i)
{
auto curr = pending.front();
pending.pop();
curr_ans += curr->val;
if (curr->left)
pending.push(curr->left);
if (curr->right)
pending.push(curr->right);
}
ans = curr_ans;
}
return ans;
}
};