Update readme.md

Author: iamAntimPal

LeetCode SQL 50 Solution/1729. Find Followers Count/readme.md

@@ -0,0 +1,82 @@
+Here’s a well-structured `README.md` for **LeetCode 1729 - Find Followers Count**, formatted for a GitHub repository:
+
+```md
+# 📊 Find Followers Count - LeetCode 1729
+
+## 📌 Problem Statement
+You are given a table **Followers** that contains the following information:
+
+- `user_id`: The ID of the user being followed.
+- `follower_id`: The ID of the user who is following.
+
+Your task is to return a list of users with their **follower count**, sorted in **ascending order of `user_id`**.
+
+---
+
+## 📊 Table Structure
+
+### **Followers Table**
+| Column Name | Type |
+| ----------- | ---- |
+| user_id     | int  |
+| follower_id | int  |
+
+- `(user_id, follower_id)` is the **primary key**.
+- Each row represents a **follower relationship** between two users.
+
+---
+
+## 📊 Example 1:
+
+### **Input:**
+#### **Followers Table**
+| user_id | follower_id |
+| ------- | ----------- |
+| 0       | 1           |
+| 1       | 0           |
+| 2       | 0           |
+| 2       | 1           |
+
+### **Output:**
+| user_id | followers_count |
+| ------- | --------------- |
+| 0       | 1               |
+| 1       | 1               |
+| 2       | 2               |
+
+### **Explanation:**
+- **User 0** has **1 follower** `{1}`.
+- **User 1** has **1 follower** `{0}`.
+- **User 2** has **2 followers** `{0, 1}`.
+
+---
+
+## 🖥 SQL Solution
+
+### ✅ **Approach:**
+1. Use `COUNT(follower_id)` to count the number of followers for each `user_id`.
+2. Use `GROUP BY user_id` to group the followers for each user.
+3. Sort the result by `user_id` in **ascending order**.
+
+```sql
+SELECT user_id, COUNT(follower_id) AS followers_count
+FROM Followers
+GROUP BY user_id
+ORDER BY user_id;
+```
+
+---
+
+## 📁 File Structure
+```
+📂 Find-Followers-Count
+│── 📜 README.md
+│── 📜 solution.sql
+│── 📜 test_cases.sql
+```
+
+---
+
+## 🔗 Useful Links
+- 📖 [LeetCode Problem](https://leetcode.com/problems/find-followers-count/)
+- 📝 [MySQL COUNT Function](https://www.w3schools.com/sql/sql_count.asp)