Skip to content

Immediate-Food-Delivery-II.md

Latest commit

 

History

History
94 lines (67 loc) · 2.99 KB

Immediate-Food-Delivery-II.md

File metadata and controls

94 lines (67 loc) · 2.99 KB

Table: Delivery

Column Name Type
delivery_id int
customer_id int
order_date date
customer_pref_delivery_date date

Description:

delivery_id is the column of unique values of this table.

The table holds information about food delivery to customers that make orders at some date and specify a preferred delivery date (on the same order date or after it).

  • If the customer's preferred delivery date is the same as the order date, then the order is called immediate; otherwise, it is called scheduled.

  • The first order of a customer is the order with the earliest order date that the customer made. It is guaranteed that a customer has precisely one first order.

Problem:

Write a solution to find the percentage of immediate orders in the first orders of all customers, rounded to 2 decimal places.

The result format is in the following example.

Example 1:

Input:

Delivery table:

delivery_id customer_id order_date customer_pref_delivery_date
1 1 2019-08-01 2019-08-02
2 2 2019-08-02 2019-08-02
3 1 2019-08-11 2019-08-12
4 3 2019-08-24 2019-08-24
5 3 2019-08-21 2019-08-22
6 2 2019-08-11 2019-08-13
7 4 2019-08-09 2019-08-09

Output:

immediate_percentage
50.00

Explanation:

  • The customer id 1 has a first order with delivery id 1 and it is scheduled.
  • The customer id 2 has a first order with delivery id 2 and it is immediate.
  • The customer id 3 has a first order with delivery id 5 and it is scheduled.
  • The customer id 4 has a first order with delivery id 7 and it is immediate.

Hence, half the customers have immediate first orders.

Solution

Approach 1:

Using direct comparison by equating order_date to customer_perf_delivery_date

SELECT 
    ROUND(AVG(order_date = customer_pref_delivery_date)*100, 2) AS immediate_percentage
FROM Delivery
WHERE (customer_id, order_date) IN (
    SELECT customer_id, MIN(order_date)
    FROM Delivery
    GROUP BY customer_id
);

Approach 2:

Using condition statement like CASE to add only when order_date equals to customer_pref_delivery_date

SELECT 
    ROUND(100 *
    SUM(CASE 
            WHEN order_date = customer_pref_delivery_date 
            THEN 1 ELSE 0 END) / COUNT(customer_id), 2) AS immediate_percentage
FROM Delivery
WHERE (customer_id, order_date) IN 
        (SELECT 
            customer_id, 
            MIN(order_date)
        FROM Delivery
        GROUP BY customer_id
        )