Given a function fn, return a new function that is identical to the original function except that it ensures fn is called at most once.
- The first time the returned function is called, it should return the same result as
fn. - Every subsequent time it is called, it should return
undefined.
fn = (a,b,c) => (a + b + c), calls = [[1,2,3],[2,3,6]]
// Output: [{"calls":1,"value":6}]Explanation :
const onceFn = once(fn);
onceFn(1, 2, 3); // 6
onceFn(2, 3, 6); // undefined, fn was not called
fn = (a,b,c) => (a * b * c), calls = [[5,7,4],[2,3,6],[4,6,8]]
// Output: [{"calls":1,"value":140}]Explanation :
const onceFn = once(fn);
onceFn(5, 7, 4); // 140
onceFn(2, 3, 6); // undefined, fn was not called
onceFn(4, 6, 8); // undefined, fn was not called
callsis a valid JSON array1 <= calls.length <= 101 <= calls[i].length <= 1002 <= JSON.stringify(calls).length <= 1000