Given an integer array arr and a filtering function fn, return a filtered array filteredArr.
The fn function takes one or two arguments :
- arr[i] - number from the arr
- i - index of arr[i]
filteredArrshould only contain the elements from thearrfor which the expressionfn(arr[i], i)evaluates to a truthy value. A truthy value is a value whereBoolean(value)returns true.
Please solve it without the built-in Array.filter method.
arr = [0,10,20,30], fn = function greaterThan10(n) { return n > 10; }
// Output: [20,30]Explanation:
const newArray = filter(arr, fn); // [20, 30]
The function filters out values that are not greater than 10
arr = [1,2,3], fn = function firstIndex(n, i) { return i === 0; }
// Output: [1]Explanation:
fn can also accept the index of each element
In this case, the function removes elements not at index 0
arr = [-2,-1,0,1,2], fn = function plusOne(n) { return n + 1 }
// Output: [-2,0,1,2]Explanation:
Falsey values such as 0 should be filtered out
0 <= arr.length <= 1000109 <= arr[i] <= 109