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encourage playing along at home
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source_md/making-our-own-types-and-typeclasses.md

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@@ -1842,6 +1842,9 @@ We see that `t` has to produce a concrete value too and that it takes two argume
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And knowing that `a` has a kind of `k` and `j` has a kind of `k -> *`, we infer that `t` has to have a kind of `k -> (k -> *) -> *`.
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Wow.
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Is that actually correct?
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Try `:k Tofu` to find out.
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OK, so let's make a type with a kind of `k -> (k -> *) -> *`.
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Here's one way of going about it.
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