I wish i knew what a statement was

Author: AndrewRayCode

.bashrc

@@ -1225,12 +1225,12 @@ lbl() {
     fi
 }
 
-# Execute an apex statement against an environment
+# Execute an apex expression against an environment
 exp() {
     if [[ -z "$1" ]] || [[ -z "$2" ]]; then
-        echo "Execute an expression, and print the output. Takes the apex statement you pass in and wraps it in a System.debug() call."
+        echo "Execute an expression, and print the output. Takes the apex expression you pass in and wraps it in a System.debug() call."
         echo "Pass quiet or q as the last paremeter to supress notification messages"
-        echo "Usage: exp [ORG_ID] [STATEMENT_TO_EVALUATE] ['quiet' | 'q']"
+        echo "Usage: exp [ORG_ID] [EXPRESSION_TO_EVALUATE] ['quiet' | 'q']"
         return 1
     fi
 
@@ -1253,12 +1253,13 @@ exp() {
     # We need to find from the start of USER_DEBUG to the next non-debug line.
     # Notice "b" is put on a line by itself, making it tricky to include in output
 
-    sfdx force:apex:execute -u "${1}" -f /dev/stdin<<<"$apexCommand" | # Execute the statement inside a system.debug(). execute expects a file, so use <<< trick to make it seem like a file
+    sfdx force:apex:execute -u "${1}" -f /dev/stdin<<<"$apexCommand" | # Execute the expression inside a system.debug(). execute expects a file, so use <<< trick to make it seem like a file
         pcregrep -M 'USER_DEBUG(.|\n)+?([\d]{2}:[\d]{2}:[\d]{2})' | # find debug line, and try to search up to the next apex ouptut line, starting with dd:dd:dd
         sed '$d' | # remove the last line, which is the first non-debug line
         sed 's/.*\|//' # find everything after the last pipe, which will be the debugged output
 }
 
+# Execute an apex expression against an environment
 stmt() {
     if [[ -z "$1" ]] || [[ -z "$2" ]]; then
         echo "Execute a statement or list of statements"