Given an integer array nums and an integer val, remove all occurrences of val in nums in-place. The order of the elements may be changed. Then return the number of elements in nums which are not equal to val.
Consider the number of elements in nums which are not equal to val be k. To get accepted, you need to do the following:
- Change the array
numssuch that the firstkelements contain the elements which are not equal toval. - The remaining elements of
numsare not important. - Return
k.
The judge will test your solution with the following code:
int[] nums = [...]; // Input array
int val = ...; // Value to remove
int[] expectedNums = [...]; // The expected answer with correct length.
// It is sorted with no values equaling val.
int k = removeElement(nums, val); // Calls your implementation
assert k == expectedNums.length;
sort(nums, 0, k); // Sort the first k elements of nums
for (int i = 0; i < k; i++) {
assert nums[i] == expectedNums[i];
}If all assertions pass, then your solution will be accepted.
Input:
nums = [3,2,2,3], val = 3
Output:
2, nums = [2,2,_,_]
Explanation: Your function should return k = 2, with the first two elements of nums being 2. The underscores represent any values left beyond k that are not important.
Input:
nums = [0,1,2,2,3,0,4,2], val = 2
Output:
5, nums = [0,1,4,0,3,_,_,_]
Explanation: Your function should return k = 5, with the first five elements of nums containing 0, 0, 1, 3, and 4. The underscores represent any values left beyond k that are not important.
0 <= nums.length <= 1000 <= nums[i] <= 500 <= val <= 100