Given an integer array nums sorted in non-decreasing order, remove the duplicates in-place such that each unique element appears only once. The relative order of the elements should be kept the same. Then return the number of unique elements in nums.
Consider the number of unique elements of nums to be k. To get accepted, you need to do the following:
- Change the array
numssuch that the firstkelements contain the unique elements in the order they were initially present. - The remaining elements of
numsare not important. - Return
k.
The judge will test your solution with the following code:
int[] nums = [...]; // Input array
int[] expectedNums = [...]; // The expected answer with correct length
int k = removeDuplicates(nums); // Calls your implementation
assert k == expectedNums.length;
for (int i = 0; i < k; i++) {
assert nums[i] == expectedNums[i];
}If all assertions pass, then your solution will be accepted.
Input:
nums = [1,1,2]
Output:
2, nums = [1,2,_]
Explanation: Your function should return k = 2, with the first two elements of nums being 1 and 2 respectively. The underscores represent any values left beyond k that are not important.
Input:
nums = [0,0,1,1,1,2,2,3,3,4]
Output:
5, nums = [0,1,2,3,4,_,_,_,_,_]
Explanation: Your function should return k = 5, with the first five elements of nums being 0, 1, 2, 3, and 4 respectively. The underscores represent any values left beyond k that are not important.
1 <= nums.length <= 3 * 10^4-100 <= nums[i] <= 100numsis sorted in non-decreasing order.